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Can someone solve 3x=12x^2 and explain?

Please help!

5 Answers

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  • ?
    Lv 7
    9 years ago
    Favorite Answer

    3x(4x-1)=0

    x=0

    x=1/4

    ~David

  • ?
    Lv 7
    9 years ago

    3x = 12x^2

    3x(4x - 1) =0

    Solutions:

    x = 0

    x = 1/4

  • 9 years ago

    Put in the form of a quadratic equation, 12x^2 - 3x = 0. Factor to get 3x(4x - 1) = 0. So either 3x = 0, in which case x = 0 (divide both sides by 3), or 4x - 1 = 0, in which case x = 1/4 (add 1 to both sides, then divide both sides by 4).

    Source(s): Retired math teacher
  • DWRead
    Lv 7
    9 years ago

    3x = 12x²

    One obvious solution is x = 0.

    To look for other solutions, assume x ≠ 0, then divide both sides by 3x.

    1 = 4x

    x = 1/4

    :::::

    Another way to solve:

    12x² - 3x + 0 = 0

    By the quadratic formula,

    x = [3 ± √(3² - 4·12·0)]/(2·12)

    = [3 ± √(3²)]/24

    = 1/8 ± 1/8

    = 0, 1/4

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  • Pranil
    Lv 7
    9 years ago

    12x² = 3x

    12x² – 3x = 0

    3x(4x – 1) = 0

    3x = 0 or (4x – 1) = 0

    x = 0 or x = 1/4

    ----

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