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Carsmypets222
Carsmypets222 asked in Science & MathematicsMathematics · 9 years ago

2m^2/3 - 7m^1/3+5 = 0 ........ answers: 1, 125/8----I need the steps, since i cant figure out how to do it?

2 Answers

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  • Philo
    Lv 7
    9 years ago
    Favorite Answer

    it's a quadratic. replace m^(1/3) with u. then

    2u² - 7u + 5 = 0

    (2u - 5)(u - 1) = 0

    u = 5/2 or u = 1

    m^1/3 = 5/2

    m = (5/2)^3 = 125/8

    m^1/3 = 1

    m = 1^3 = 1

  • MechEng2030
    Lv 7
    9 years ago

    2m^(2/3) - 7m^(1/3) + 5 = 0

    2m^(2/3) - 5m^(1/3) - 2m^(1/3) + 5 = 0

    m^(1/3)*(2m^(1/3) - 5) - (2m^(1/3) - 5) = 0

    (2m^(1/3) - 5)(m^(1/3) - 1) = 0

    2m^(1/3) - 5 = 0 or m^(1/3) = 1

    m = 125/8 or 1

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