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mishraanoopam
mishraanoopam asked in Science & MathematicsMathematics · 9 years ago

easy geometry question?

On triangle ABC, points D and E are chosen on line segments AB and AC, respectively. The lines CD and BE intersect at K, within triangle ABC. If [DKB]=56,[BKC]=84 and [KEC]=90, what is [ADKE]?

Note: [PQRS] denotes the area of the figure PQRS.

2 Answers

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  • Pranil
    Lv 7
    9 years ago
    Favorite Answer

    [KEC]/[DKB] [ADKE]/,[BKC]

    90/56 = [ADKE]/84

    [ADKE] = 90 × 84/56 = 135

    ----

  • rst
    Lv 5
    9 years ago

    Pranil answer may work

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