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Help me! i dont understand this equation!?
Simplify: x^3 - 36x over x^2 + 7x + 6 divided by 6x^2 - x^3 over x^2 +x
I just started trigonometry and i have no idea wht to do with this one equation. I did every other one but this ones too hard X_X please tell me how to do it. :( PLEEEEEEEEEEAAAAAAAAAAAAAAAASSSSSSSSSSSSSSSSSSEEEEEEEEEEEEEEEEE
2 Answers
- hayharbrLv 79 years agoFavorite Answer
Factor them, flip the second changing to multiply, then cancel.
x (x^2 - 36) x(x + 1)
---------------- • ------------
(x + 6)(x + 1) x^2(6 - x)
x(x+6)(x-6) x(x + 1)
---------------- • ------------
(x + 6)(x + 1) x^2(6 - x)
Cancel the x^2 with the two x's, and the (x + 1) and the (x + 6)and the (6-x) with (x-6) which is -1
and that's all that's left: -1
- Anonymous4 years ago
What you have published are inequalities, not equations. sparkling up them interior the comparable way you sparkling up equations, by using doing the comparable operation (upload, subtract, multiply or divide) to the two factors. however, whilst fixing inequalities, in case you multiply or divide by using a adverse quantity, the experience of the inequality differences. case in point 4 > 3 If I multiply the two factors by using -2 -8 > - 6 is not authentic, yet - 8 < - 6 is authentic. x + 7 > 12 x > 5 {subtract 5} 5(2x - a million) > 5 2x - a million > a million {divide by using 5} 2x > 2 {upload a million} x > a million {divide by using 2} 3x + 11 > 35 3x > 24 {subtract 11} x > 8 {divide by using 3} occasion of the aforementioned exception 5 - x > 3 - x > - 2 {subtract 5} x < 2 {multiply by using -a million} in case you look on the unique inequality, you notice that this is authentic in basic terms whilst x is under 2