Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Statistics probability distribution function?

given F(x,y)=K(X^2)(Y^2)

0<=x<=1, 0<=y<=1

find value of K for this to be a valid distribution function?

Anyone know how to do this? I have only found constant values in a density function before.

Thanks for any responses in advance.

2 Answers

Relevance
  • ?
    Lv 6
    9 years ago
    Favorite Answer

    Find K such that F(x,y)=K(x^2)(y^2) = 1 for x=1 and y=1.

    And so, K=1.

  • 4 years ago

    i have forgotten each little thing I ever knew about mgf's, yet judging from what you've written, does no longer that only be a binomial distribution with p = .6 and n = 3, with a advise of one million.8 and a variance of .seventy 2? Or am I undrthinking this? i imagine you dropped an exponent marker some cases, yet no longer positive.

Still have questions? Get your answers by asking now.