Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Mathematics word problem leading in equation?
A father is six times as old as the son. Four years ago the father was ten times as old as his son.
Find the
1. son's age
2. Father's age
3. Son's age in 3yrs times.
2 Answers
- brainyandyLv 69 years agoFavorite Answer
Son's age = x So Dad's age = 6x
Four years ago:
Son's age = x - 4 So dad's age was 10(x - 4). But if dad's age is 6x then four years ago his age would have been 6x - 4.
So 6x - 4 = 10(x - 4)
6x - 4 = 10x - 40. Take 6x from both sides and add 40 to both sides.
4x = 36
x = 9. So:
1. Son's age is 9
2. father's age is 54
3. Son's age in 3 years time is 12.
- Anonymous9 years ago
x=sons age y=fathers age x+3=sons age on 3 years
y=6x
y-4=10(x-4)
y-4=10x-40
+4 +4
y=10x-36
5(y=6x)
-3(y=10x-36)
5y=30x
-3y=-30x+108
______________ -
2y=108
________
2
y=54
y=6x
54=6x
_______
6
9=x
x+3=12
The father is 54
The son is 9
The son will be 12 in three years.
