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Help With Calculus AB? :)?
Please help me with these problems.
Thank youu :D
If x^2 + xy = 10, then when x = 2, dy/dx
1 Answer
- SuperLv 49 years agoFavorite Answer
Forget for a second that we want to know anything about the function when x = 2.
x^2 + xy = 10
Subtract x^2 from both sides
xy = 10 - x^2
Divide by x
y = (10-x^2)/x = 10*x^(-1)-x
Take the derivative
dy/dx = 10*(-1)*x^(-2)-1=-1-10/x^2
So dy/dx, when x is 2, will be -1-10/(2)^2 = -14/4 = -7/2
Hopefully I didn't make any mistakes. Check my work, and make sure you understand it.
