Algebra 2 help again pleeeasee?

√(4t - 7) + 4 = -3

√(4t - 7) = -7

4t - 7 = 49

4t = 56

t = 14

However, plugging in 14 for t gives a false statement. The extraneous solution is 14.

√(5x - 7) = √(3x + 3)

5x - 7 = 3x + 3

5x = 3x + 10

2x = 10

x = 5

√(4t - 7 ) + 4 = -3

√(4t - 7 ) = -7

4t - 7 = 49

4t = 56

t = 8 which doesn't check. empty set

5x-7=3x+3 so 2x =10

x = 5 which checks

First one, square everything and the 4 outside.

Leaves you with this: 4t-7 +16=9

Second one should have this after squaring both sides: 5x-7=3x+3 ----- 2x-7=3 ---- Solve for x

if you can isolate the radical as a single term on one side of the equation

you can square both sides

sqrt(4t-7)= -3

square both sides

4t-7=9

4t=16

t=4

sqrt(5x-7)=sqrt(3x+3)

square both sides

5x-7=3x+3

2x=10

x=5

oops

first one

sqrt(4t-7)+4= -3

sqrt(4t-7)= -7

square both sides

4t-7= 49

4t=56

t=+/-sqrt(56)=+/-2sqrt(14)

a million - (4/(x+6)) = 4/x rewrite first component as: (x+6)/(x+6) - (4/(x+6)) which would be decreased to: (x + 2)/(x+6) you're able to come across a undemanding denom. between the two: multiply the left component via (x/x) and the main appropriate component via (x+6/x+6) this will supply you: (x^2+2x)/(x^2+6x) = (4x + 24)(x^2+6x) B/c the denom. are comparable they are able to be omitted, giving: x^2 + 2x = 4x + 24 which would be written as: x^2 - 2x - 24 = 0 that's: (x - 6)(x+4) = 0 hence x = 6 or -4 rewrite

what mr cool said EXCEPT 14 will work for t as -7 x -7 does equal 49