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Help with a genetics problem?
The Galapagos hawk has a polyandrous (one female, many male) mating system, in
which a single female controls a harem of males and is the sole mother of all babies in
that social group, which can contain up to 8 males, but there is only a single baby
produced in each year. In another species, the Swainson’s hawk, a single male and female
pair up and have a single baby in each year.
a. Assuming all else is equal, which species is likely to have the larger Ne and why?
b. Which species will lose heterozygosity more quickly and why?
Thanks!
1 Answer
- 8 years agoFavorite Answer
The second group where only one male and female are mating will lose heterozygosity more quickly. This is because their gene pool is much smaller than the larger group consisting of 8 males and 1 female mating. Smaller populations result in the loss of genetic variability (Heterozygosity)