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hmm asked in Science & MathematicsBiology · 8 years ago

Help with a genetics problem?

The Galapagos hawk has a polyandrous (one female, many male) mating system, in

which a single female controls a harem of males and is the sole mother of all babies in

that social group, which can contain up to 8 males, but there is only a single baby

produced in each year. In another species, the Swainson’s hawk, a single male and female

pair up and have a single baby in each year.

a. Assuming all else is equal, which species is likely to have the larger Ne and why?

b. Which species will lose heterozygosity more quickly and why?

Thanks!

1 Answer

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  • 8 years ago
    Favorite Answer

    The second group where only one male and female are mating will lose heterozygosity more quickly. This is because their gene pool is much smaller than the larger group consisting of 8 males and 1 female mating. Smaller populations result in the loss of genetic variability (Heterozygosity)

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