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Please help me with genetics?
What is the value of H (heterozygosity) for a population of pupfish in Hardy-Weinberg
Equilibrium for a microsatellite locus that has 8 alleles and the following frequencies of
homozygotes in the population: A1A1 = 0.01, A2A2 = 0.01, A3A3 = 0, A4A4 = 0.05,
A5A5 = 0.07, A6A6 = 0.01, A7A7 = 0.02, A8A8 = 0.03?
If you could explain this to me it would really help - this is NOT my homework - I am reviewing for a test!! Thank you
2 Answers
- JonahLv 78 years agoFavorite Answer
The total portion of homozygotes is
0.01 + 0.01 + 0 + 0.05 + 0.07 + 0.01 + 0.02 + 0.03 = 0.20
The remainder of the population must be heterozygoes. 1 -0.2 = 0.8
- 4 years ago
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