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fritya56
Lv 6
fritya56 asked in Science & MathematicsMathematics · 8 years ago

surds in form a square root 3?

6 / square root 3 + square root 75 .

does that make 11 square root three ?

5 Answers

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  • Argent
    Lv 7
    8 years ago
    Favorite Answer

    6/√3 + √75 = (6/√3)(√3/√3) + √(25·3)

    = (6√3)/3 + 5√3

    = 2√3 + 5√3

    = 7√3.

  • Glipp
    Lv 7
    8 years ago

    6/√3 + √75 = 2√3 + 5√3 = 7√3

  • Krishnamurthy
    Lv 5
    8 years ago

    6/√3 + √75

    = (6√3 / √3√3) + √25√3

    = 6√3/3 + 5√3

    = 2√3 + 5√3

    = 7√3

  • Anonymous
    8 years ago

    6/√(3) + √(75) = 2√(3) + 5√(3) = 7√(3)

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  • Anonymous
    4 years ago

    /23 + 3/40 /23 + 3 * /20 * /2 /23 + 3 * 2/5 * /2 /23 + 6/10 you won't be able to simplify the /23 anymore so which you need to depart or no longer that is. even although with the three/40 you could destroy /40 down into smaller factors.

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