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Another Trig Equation?
I'm more interested in how to do this problem than just having the answer. It's really bothering me:
sin x - 2sin(x)cos(x) = 0
So far, I have sin x = 2sin(x)cos(x)
I thought of dividing by cos(x) and having
tan(s) = 2sin(x)
I don't know where to go from there.
Thank you!
1 Answer
- 8 years agoFavorite Answer
why don't you just factor instead?
sin(x) * (1 - 2cos(x)) = 0
sin(x) = 0
x = pi * k
1 - 2cos(x) = 0
1 = 2cos(x)
cos(x) = 1/2
x = pi/3 + 2pi * k , 5pi/3 + 2pi * k
x = (pi/3) * (1 + 6k) , pi * k , (pi/3) * (5 + 6k)
k is an integer