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Algebra temperature question...?
A travel mug of 92 degree Celsius coffee is left on the roof of a parked car on a cold winters day. The temperature of coffee after t minutes is given by H=92(2)^(-t/11). After how many minutes will the coffee be lukewarm (30 degrees Celsius)?
t= ?
3 Answers
- Michelle ElleLv 68 years agoFavorite Answer
H=92(2)^(-t/11)
30=92(2)^(-t/11)
0.326=(2)^(-t/11)
ln 0.326 = (-t/11) ln 2
-1.6167 = (-t/11)
t= 17.78 minutes or 17 minutes and 47 seconds
Source(s): I hope this helps - GrassyLv 78 years ago
H=92(2)^(-t/11) = 30
(2)^(-t/11) = 30/92
-t/11) = -15/46 / log (2)
t = 165/46 / log (2) = 17.777 minutes
- ComoLv 78 years ago
30/92 = 2^(-t/11)
2^(t/11) = 92/30
(t/11) log 2 = log (92/30)
t = 11 log(92/30) / log 2
t = 17.8 minutes
