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Uni algebra, anyone help?

The area of a wetland drops by 1/3 every 5 years. What percent of its total area disappears after 25 years?

2 Answers

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  • 8 years ago
    Favorite Answer

    Let the original area = (A0).

    After the 1st. 5-year period, lost area = (A0)/3.

    So remaining area, (A1) = (A0) - (A0)/3 = (2/3).(A0).

    After the 2nd. 5-year period, lost area = (A1)/3 = (1/3).(2/3).(A0)

    So remaining area, (A2) = (A1) - (1/3).(2/3).(A0) = (2/3).(A0) - (1/3).(2/3).(A0) = (2/3)².(A0)

    After the 3rd. 5-year period, lost area = (A2)/3 = (1/3).(2/3)².(A0).

    So remaining area, (A3) = (A2) - (1/3).(2/3)².(A0) = (2/3)².(A0) - (1/3).(2/3)².(A0) = (2/3)^3.(A0)

    Hence, after the nth. 5-year period,

    lost area = (1/3).(2/3)^(n - 1).(A0).

    For a time-period of 25 years, 25 years = 5 X 5-year periods.

    Hence, for 25 years, n = 5.

    Therefore, after 25 years, the lost area = (1/3).(2/3)^4.(A0) = 0.889.(A0)

    So the fractional loss of original area = 0.889(A0) ÷ (A0) = 0.889 = 88.9%.

    Skywave.

  • 8 years ago

    (2/3) of the original area remains after each 5-year period. In 25 years, there are 5 such periods. The amount lost is

    .. 1 - (2/3)^5 = 0.868313 ≈ 86.8%

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