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Suppose that ln a= 2011?
Calculate ln((a^2011)/(e^2011))
2 Answers
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- Wayne DeguManLv 78 years agoFavorite Answer
ln[(a^2011)/(e^2011)]
=> ln(a^2011) - ln(e^2011)
=> 2011(ln a) - 2011(ln e)
i.e. 2011(2011) - 2011
so, 2011(2010) = 4,042,110
:)>
- DWReadLv 78 years ago
ln(a²⁰¹¹/e²⁰¹¹) = ln((a/e)²⁰¹¹)
= 2011·ln(a/e)
= 2011(ln(a) - ln(e))
= 2011(2011 - 1)
= 2011·2010
= 4,042,110
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