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Calculus 2 Kepler Law finding Minor axis?
A comet has an elliptical orbit with the sun at one focus and has an eccentricity of e ≈ 0.928. The length of the major axis of the orbit is approximately 620 astronomical units. The minimum distance (perihelion) from the sun to the comet is
r = a(1 − e)
and the maximum distance (aphelion) is
r = a(1 + e).
1) Length of its Minor axis = ????
Thanks in advance!
1 Answer
- King LeoLv 78 years agoFavorite Answer
length of major axis
r = a(1 + e)
L = 2r
L = a(1 + 0.928)
L = 1.928a
620 = 1.928a
a = 620/1.928
length of minor axis
L = 2r
L = 2a(1 - e)
L = 2(620/1.928)(1 - 0.928)
L = 46.3 astronomical units
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