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Physics help please? Best answer!?
The work function of a certain photoemissive material is 2 electrovolts. If 5-electrovolt protons are incident on the material, the maximum kinetic energy of the ejected photoelectrons will be:
A- 7eV
B- 5eV
C- 3 eV
D- 2.5 eV
1 Answer
- callmemrwafflesLv 48 years agoFavorite Answer
if the work function is 2 eV, this energy should be subtracted from the incident photons. therefore the ejected photoelectonrs should have a maximum energy of 5 - 2 = 3 eV
