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Two towers face each other separated by a distance d = 100 feet. What is the height of the second tower?
As seen from the top of the first tower, the angles of depression of the second tower's base and top are 56 degrees and 32 degrees, respectively.
1 Answer
- dennisLv 68 years agoFavorite Answer
Let the first tower be CA(C at the bottom) and the second tower be BT(B at the bottom)
From your information angle BAC = 34 so BA = 100/sin 34
Also angle TAC = 58 so that AT = 100/sin 58.
We can now use the cosine rule on triangle BTA where angle BAT = 24 to get the height BT of the second tower
BT^2 = BA^2 + TA^2 - 2 BA*TA*cos 24.
