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1^infinity is easily assumed to be 1. But it is taken under the category of in determinant just as 0/0. Why?
3 Answers
- KevinMLv 78 years agoFavorite Answer
Because it depends on how you approach infinity.
If you approach 0/0 as 0/1, 0/0.1, 0/0.001.... it approaches infinity. If you take it as 1/1, .01/.1, .0001/.01 ... it approaches 0.
The same with 1^infinity. The limit "e" is known as:
lim (n->infinity) (1 + 1/n)^n
This looks like 1^infinity, but it's NOT 1. It's 2.71828....
- wendaloreLv 78 years ago
Beats the hell out of me, True!
(I just love that phrase, and never get a chance to use it!)
