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if n!*(n+2)!=(2n)! find the value of n?

3 Answers

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  • 8 years ago
    Favorite Answer

    n! * (n + 2)! = (2n)!

    n! * (n + 2)! = (2n)(2n - 1)(2n - 2)(2n - 3) ....

    n! * (n + 2)! = 2(n!)(2n - 1)(2n - 3)(2n - 5)...

    (n + 2)! = 2(2n - 1)(2n -3 )(2n - 5)...

    Will return to this

  • 8 years ago

    n=3

  • RAY G
    Lv 7
    8 years ago

    3

    3! * 5! = 6*120 = 720 = 6! = (2*3)!

    I admit I did this by graphing. At first glance, an analytical solution looks complicated.

    There are other, negative, solutions if you use the generalisation of the factorial function in terms of the gamma function Γ(n) = (n - 1)!

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