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if n!*(n+2)!=(2n)! find the value of n?
3 Answers
- MechEng2030Lv 78 years agoFavorite Answer
n! * (n + 2)! = (2n)!
n! * (n + 2)! = (2n)(2n - 1)(2n - 2)(2n - 3) ....
n! * (n + 2)! = 2(n!)(2n - 1)(2n - 3)(2n - 5)...
(n + 2)! = 2(2n - 1)(2n -3 )(2n - 5)...
Will return to this
- RAY GLv 78 years ago
3
3! * 5! = 6*120 = 720 = 6! = (2*3)!
I admit I did this by graphing. At first glance, an analytical solution looks complicated.
There are other, negative, solutions if you use the generalisation of the factorial function in terms of the gamma function Î(n) = (n - 1)!