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... asked in Science & MathematicsPhysics · 8 years ago

Help with AS Physics question?

Please could you help me with this AS Level physics question:

A motorcycle passes through a green light at a speed of 15 m/s. At the same instant, a car accelerates from rest alongside the motorcycle. If the acceleration of the car is 3 m/s^2, find the distance after the traffic lights where the car & motorcyclist meet.

Thanks!

1 Answer

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  • DaveWH
    Lv 7
    8 years ago
    Favorite Answer

    Recall that

    speed = distance / time

    acceleration = distance / time^2

    15 = m / t

    m = 15t

    3 = m / t^2

    m = 3t^2

    Since the two distances have to be the same, we can work out the time at which the meet by equating the distances

    3t^2 = 15t

    3t = 15

    t = 5 seconds.

    We can now substitute this into either of the equations above to find the distance

    m = 15t = 75 meters

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