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Calculus Help Please? 10 points!?
The directions say,
Find an equation of the tangent line to the curve at the given point.
y=square rootx, (1,1)
Sorry I could not type the radical sign on this keyboard. The "x" is under a radical sign.
The point (1,1) is given.
I am unsure how to approach this HW problem.
2 Answers
- Marley KLv 78 years agoFavorite Answer
one of the definitions of the derivative is that it is the slope of the tangent line.
so . . .
given y = √x, take the derivative:
y = x^1/2
y ' = (1/2)x^(-1/2) = 1/(2√x)
put 1 in for y to find the slope:
m = 1/2
now you can use point-slope form to find the equation:
y - 1 = (1/2)(x - 1)
y = (1/2)x + 1/2
that's it! ;)
- Anonymous8 years ago
1+1=11
