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Mean/Z-Score Question/Probability...need help asap!?

The mean of a standardized statistics test is 82 with a standard deviation of 4. The test scores are normally distributed.

a. What is the probability that a person scores between 74 and 90?

b. What percent of people will score between 78 and 86?

c. What is the z-score associated with a test score of 75?

d. What does a z-score measure?

1 Answer

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  • cidyah
    Lv 7
    8 years ago
    Favorite Answer

    a)

    μ = 82

    σ = 4

    standardize x to z = (x - μ) / σ

    P( 74 < x < 90) = P[( 74 - 82) / 4 < Z < ( 90 - 82) / 4]

    P( -2 < Z < 2) = 0.9772 -0.0228 =0.9544

    find the area below 2; find the area below -2; subtract.

    (From Normal probability table)

    b)

    μ = 82

    σ = 4

    standardize x to z = (x - μ) / σ

    P( 78 < x < 86) = P[( 78 - 82) / 4 < Z < ( 86 - 82) / 4]

    P( -1 < Z < 1) = 0.8413 -0.1587 = 0.6826

    find the area below 1; find the area below -1; subtract.

    (From Normal probability table)

    c)

    (75-82)/4 = -7/4 = -1.75

    d)

    How many standard deviation from the mean a value is.

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