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Mean/Z-Score Question/Probability...need help asap!?
The mean of a standardized statistics test is 82 with a standard deviation of 4. The test scores are normally distributed.
a. What is the probability that a person scores between 74 and 90?
b. What percent of people will score between 78 and 86?
c. What is the z-score associated with a test score of 75?
d. What does a z-score measure?
1 Answer
- cidyahLv 78 years agoFavorite Answer
a)
μ = 82
σ = 4
standardize x to z = (x - μ) / σ
P( 74 < x < 90) = P[( 74 - 82) / 4 < Z < ( 90 - 82) / 4]
P( -2 < Z < 2) = 0.9772 -0.0228 =0.9544
find the area below 2; find the area below -2; subtract.
(From Normal probability table)
b)
μ = 82
σ = 4
standardize x to z = (x - μ) / σ
P( 78 < x < 86) = P[( 78 - 82) / 4 < Z < ( 86 - 82) / 4]
P( -1 < Z < 1) = 0.8413 -0.1587 = 0.6826
find the area below 1; find the area below -1; subtract.
(From Normal probability table)
c)
(75-82)/4 = -7/4 = -1.75
d)
How many standard deviation from the mean a value is.