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Help with Continuous Random Variables?
I'm given the following density function:
f(x) = (3/2)sqrt(x) ; 0<x<1
0 ; elsewhere
Find F(x)
I did the integration, and what I came up with was
F(x) = 0 ; x #< 0 (please note: I'm using the # to mean "or equal to")
x^(3/2) ; 0<x<1
1 ; x #>1
This is pretty close, however, the correct answer has different # placements:
F(x) = 0 ; x < 0
x^(3/2) ; 0#<x<1
1 ; x #>1
I don't understand what I'm doing wrong. If f(x) is 0 until x goes ABOVE zero, then why does F(x) say x has to be BELOW zero to create F(x)=0, and x^(3/2) starts at zero?
I hope this isn't too confusing, I wasn't entirely sure how else to word it. Any help is greatly appreciated.
1 Answer
- nleLv 78 years agoFavorite Answer
It seems that you're doing nothing wrong.
The only difference is the sign <= or < which is not very important.