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graphing equations, slope intercept form?
Homework Help
Graph each equation. Determine the solution of the system of the equations.
x=y
6x=4y-8
I know the answer for line one (x=y) is (0,0) and (2,2)
and the answer for line 2 (6x=4y-8) is (0,2) and (-4,-4)
When I work this problem out this is what I do:
6x=4y-8
-4y=-6x-8
/-4 /-4
y=1.5x+2
(double it for better numbers)
y=3x+4
slope intercept form is y=mx+b (I know that) and I know rise over run.. I just don't understand what I'm doing wrong.. how did they get the 2 line points? Someone please explain!
1 Answer
- ?Lv 67 years ago
Actually, when you do this, you're trying to find the point where the two lines intersect. What you've done is finding two points on a line.
The point of intersection on two lines is such that the point (x,y) plugged into both equations is true. That's to say that the x in the first equation equals the x in the second equation, same with the "y".
So, your first equation is x = y. We can substitute x for y in the second equation, because they're equal.
so 6x = 4x -8
2x = -8
and x = -4
Which means y = -4
So the solution is (-4, -4)
