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How do you solve the x-coordinate for this equation?
y=(3x-1)^4
I cant seem to figure out how to obtain the x-coordinate from this. I know you must make y=0, but I don't know what to do after that!
btw the answer in the book says 5/6....i dont know how they got that!
2 Answers
- Wayne DeguManLv 77 years agoFavorite Answer
You are trying to find where the function y = (3x - 1)⁴ crosses the x-axis??
so, (3x - 1)⁴ = 0
=> 3x - 1 = 0
=> 3x = 1
i.e. x = 1/3...so, point (1/3, 0)
The function touches the x-axis at this point.
Here is a sketch:
http://www.wolframalpha.com/input/?i=y+%3D+%283x+-...
:)>
Source(s): wolframalpha.com - 7 years ago
you need the y coordinate of the point at which you are trying to find the x coordinate. If you make y=0 will only give you the point on the curve where it crosses or touches x-axis.
if you want x coordinate when y=0 you have (3x-1)^4 =0 ie x =1/3
