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Can someone help me with this parabola problem?
Find the equation of the parabola that passes through the ordered pairs (0, 4), (3, 7), and (-2, 12).
I dont know where to start with this problem. So if you could take me through the steps, itd be much appreciated. Thanks in advance.
1 Answer
- GeronimoLv 77 years agoFavorite Answer
y = ax² + bx + c
4 = a(0)² + b(0) + c ... evaluated at (0, 4)
4 = c
y = ax² + bx + 4
7 = a(3)² + b(3) + 4 ... evaluated at (3, 7)
3 = 9a + 3b ... equation 1
12 = a(-2)² + b(-2) + 4 ... evaluated at (-2, 12)
08 = 4a – 2b ... equation 2
solve equations 1 & 2: a = 1, b = -2
y = x² – 2x + 4 ◀◀
