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How to find this first + second derivative?
Stuck on this practice problem, forget the steps when the ln is thrown in there.
f(x) = √e^x ln(x)
The ln(x) is NOT under the square root sign.
Any help/advice would be greatly appreciated and helpful!
1 Answer
- DaveLv 67 years ago
f(x) = √e^x ln(x)
f(x) = e^(x/2) ln(x)
f ' (x) = 1/2 e^(x/2) ln(x) + e^(x/2) / x
f '' (x) = 1/2[1/2 e^(x/2) ln(x) + e^(x/2) / x] + -e^(x/2)/x^2 + 1/2 e^(x/2) / x <-----------------------------(answer)