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Another first and second derivative problem?
This group of problems has fractions on the outside, stumped again..
f(x) = (1+e^4x)^3/2
Have to find first and second derivative
2 Answers
- ?Lv 77 years agoFavorite Answer
f(x) = (1+e^4x)^3/2
Use the Chain Rule to find f '(x)
f '(x) = (3/2)(1+e^4x)^(1/2) • (e^4x)(4) = 6e^(4x)(1+e^4x)^(1/2)........ANS
Use the Product Rule to find f "(x)
f "(x) = 6 [e^(4x) • (1/2)(1+e^4x)^(-1/2)(e^4x)(4) + (4e^(4x)) • (1+e^4x)^(1/2))......ANS
...........(you'll need to simplify f"(x))
- ?Lv 77 years ago
Assume
f(x) = (1+e^4x)^(3/2) ---> f '(x) = 6e^(4x) (1+e^4x)^(1/2)
and use the product rule to workout f "(x)