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Implicit differentiation question?

Using implicit differentiation how would I find dy/dx for xy - e^(xy) = 7

Never done one of these with using an exponential function e. Any help would be greatly appreciated!

2 Answers

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  • Ray S
    Lv 7
    7 years ago

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    Note:   The derivative of eᵁ wrt x is eᵁ(du/dx).

               So, for u=xy,

               d/dx(eˣʸ) = eˣʸ(d/dx(xy)) = eˣʸ(xy'+y*1) = eˣʸ(xy'+y)

                       xy - eˣʸ = 7

    (xy'+y*1) - eˣʸ(xy'+y) = 0        ← Differentiated implicitly wrt x ... Now, expand and collect y'-terms

    xy' + y - eˣʸxy' - eˣʸy = 0

                   xy' - eˣʸxy' = eˣʸy - y

                   (x - eˣʸx)y' = (eˣʸ - 1)y

                                         (eˣʸ - 1)y

                                y' = —————–

                                          x - eˣʸx

                                         (eˣʸ - 1)y

                                y' = —————–            ← ANSWER

                                         x(1 - eˣʸ)

    Have a good one!

    ——————————————————————————————————————

  • Anonymous
    7 years ago

    The derivative of e^x is e^x. Here it's e^xy, so use chain rule for that. Then when solving for dy/dx you'll have to use ln to get rid of the e. Hope that helps

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