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Solve for t : |6−4/7t|+7=9
The corporate profits for various U.S. industries vary from year to year. An approximate model for profits of U.S. "communications companies" during a given year between 1990 and 1997 is given by
P=−3400|x−5.5|+36000
where P is the annual profits (in millions of dollars) and x is the number of years after 1990. Use the model to determine the years in which profits of "communication companies" were $31.5 billion ($31,500 million).
In the years and the communication companies had profits of $31.5 billion.
thank you!
1 Answer
- SpacemanLv 77 years ago
Solve for t : |6 − 4/7t| + 7 = 9
Is the t supposed to be in the denominator of 4/7 or in the numerator?
The corporate profits for various U.S. industries vary from year to year. An approximate model
for profits of U.S. "communications companies" during a given year between 1990 and 1997 is
given by
P = −3,400|x − 5.5| + 36,000
where P is the annual profits (in millions of dollars) and x is the number of years after 1990. Use
the model to determine the years in which profits of "communication companies" were $31.5
billion ($31,500 million).
P = −3,400|x − 5.5| + 36,000
P - 36,000 = −3,400|x − 5.5|
(P - 36,000)/-3,400 = |x − 5.5|
(P - 36,000)/-3,400 = x − 5.5
[(P - 36,000)/-3,400] + 5.5 = x
x = [(P - 36,000)/-3,400] + 5.5
P = 31,500
x = [(31,500 - 36,000)/-3,400] + 5.5
x = [(-4,500)/-3,400] + 5.5
x = [1.323529] + 5.5
x = 1.323529 + 5.5
x = 6.823529 ≈ 7
1990 + 7 = 1997 year of profits of $31.5 billion
-(x - 5.5) = -x + 5.5 = 5.5 - x
P = −3,400(5.5 - x) + 36,000
P - 36,000 = −3,400(5.5 - x)
(P - 36,000)/-3,400 = (5.5 - x)
(P - 36,000)/-3,400 = 5.5 - x
[(P - 36,000)/-3,400] + x = 5.5
x = 5.5 - [(P - 36,000)/-3,400]
P = 31,500
x = 5.5 - [(31,500 - 36,000)/-3,400]
x = 5.5 - [1.323529]
x = 5.5 - 1.323529
x = 4.176471 ≈ 4
1990 + 4 = 1994 year of profits of $31.5 billion
So, in the years 1994 and 1997, the communications industry
made profits of $31,500,000,000.