Solve the nonlinear system of equations?

x² - 3y² = 1 .............. Eq. 1

4x² + 3y² = 19 .......... Eq. 2

Adding the equations,

4x² + x² + 3y² - 3y² = 19 + 1

5x² = 20

x² = 20 / 5

x² = 4

x = √4

x = ± 2

Subbing 4 for x² in Eq. 1,

4 - 3y² = 1

3y² = 4 - 1

3y² = 3

y² = 3 / 3

y² = 1

y = √1

y = ± 1

Solution Set (± 2, ± 1)

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add them and solve for x...for each x value there will be 2 y values....don't forget that √x² = ± x