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I can't solve this math equation?
(x-4)^3-4(3x-16)
So I wrote out the (x-4) three times and got x^3-12x^2+38x-24
Then I distributed the -4 to the (3x-16) and got -12x+64
I then combined those two and got x^3-12x^2+26x+40
I thought I could factor by grouping but I can't get it! Could somebody try it themselves and see what they get?
Thank you :)
4 Answers
- Anonymous7 years ago
First off, the expression you wrote is not an equation, there is no equal sign in it, so either you don't have an equation, or you typed it wrong. Second, you calculated (x-4)^3 incorrectly, it may be written
x^3 -12x^2 + 48x - 64
- 7 years ago
You can use synthetic division. If you go online you could find some great videos on synthetic division it's not hard at all.
- Marley KLv 77 years ago
it's not clear what you are trying to do since it is not an equation (no equal sign). If you simplify, the constants cancel out (-64+64), then factor out an x. You can continue factoring until you get:
x(x - 6)^2
IF you are looking for the roots, set it to zero and the roots are x=0 and x=6.
that's it! ;)
