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Find the value of x for which the perimeter is a maximum?
The perimeter of a strange shape given by P= sqrt(2x-x^2) where x is the length of one side. Find the value of x for which the perimeter is a maximum.
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- NCSLv 77 years agoFavorite Answer
dP/dx = (1 - x) / √(2x - x²) = 0
Then x = 1
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