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B asked in Science & MathematicsMathematics · 7 years ago

what formula graphs a curve that goes from 0 at negative infinity, then to -1 at -1, back down to 0 at 0, then 1 at 1, and 0 at infinity?

Update:

it was on my old calculator before it died and I can't remember it for the life of me... all I can really remember is that it was really short (one line on a TI-83) and had a smooth curve that didn't go past the 1/-1 min/max...

I'm also looking for a formula that's not trig that stops at a certain height (like tan⁻¹() ) but it's not nessessary

Update 2:

found it! y=2x/(x²+1)

2 Answers

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  • Amy
    Lv 7
    7 years ago
    Favorite Answer

    y = x e^(1 - |x|)

    or some alteration of y = x e^(-x^2) should do it too.

  • ?
    Lv 4
    7 years ago

    So, f(-x) = -f(x)? Are all the y values negative on the left (x-) side and all positive on the x+ side?

    "back down to 0,0". Do you mean up to 0,0 (from left to right)?

    So, (-1, -1), (0,0), (1,1) are all on this curve?

    For example,

    y = 2/(x^3 + 1/x)

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