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If a snowball melts so that its surface area decreases at a rate of 8 cm2/min...?
Help would be greatly appreciated.
If a snowball melts so that its surface area decreases at a rate of 8 cm2/min, find the rate at which the diameter decreases when the diameter is 9 cm
2 Answers
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- Anonymous7 years agoFavorite Answer
SA = 4πr²
SA = π(2r)²
SA = πs² --- {Where s is diameter, s = 2r}
dSA/dt = 2πs ds/dt
-8 = 2π(9) ds/dt
-4/9π = ds/dt
The snowball's diameter decreases as 4/9π cm/min
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