Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Math Question , Help needed !?
Prove that the straight line (a+b)x + (a-b)y = 2ab , (a-b)x + (a-b)y = 2ab and x+y = 0 form an isosceles triangle whose vertical angle is 2tan^-1(a/b) .
2 Answers
- LearnerLv 76 years ago
Second line given as: (a - b)x + (a - b)y = 2ab
==> x + y = 2ab/(a - b) --------- (1)
3rd line given as: x + y = 0 -------- (2)
Lines at (1) & (2) are parallel. So two parallel lines can't form a triangle. Hence kindly check up your equations and update.
[As various possibilities are possible leading to different answers, I prefer not to assume any other data. You may kindly update your data]
- ted sLv 76 years ago
call the lines l1,l2, l3, ; l1 & l2 meet at ( 0 , ab / [a-b]) , l1 & l3 at ( a , - a) , l2 & l3 DON'T meet
so assume l2 is ( a -b)x + ( a - b)y = 2ab...then l1 & l2 at P1(b,b) ; l1 & l3 atP2 ( a , - a ) ,
l2 & l3 at P3( - a , a ).... | P1P2| = | P1 P3 |..thus isoceles....hmmm...vertical angle ???....
the angle at the peak is 2 arctan (a/b).....
let ß be half that angle...opposite side is a√2 . adjacent side is b√2...tan ß = a / b..note (0,0)
is the midpoint of the base P2P3
