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If a 10 kg mass has 250 J of potential energy at the top of an incline, what is its speed when it slides to the bottom of the incline?
I got 7.07 m/s, but the answer key on my physics review packet says it's 5.00 m/s...?
Here's how I tried to solve it
KE = .5mv^2
250 = .5(10)v^2
50 = v^2
v = 7.07
2 Answers
- CelineLv 46 years ago
I'm not sure how to solve it with equations and stuff but I can say that you have to think of the earth gravitational pole. There's great resistance when trying to climb up something, and once you go down you travel much faster.
- TechnobuffLv 76 years ago
PE becomes KE after going down the slope.
Velocity = sqrt.(2KE/m) = sqrt.(500/10), = 7.07m/sec.
So unless you are failing to account for friction, or have made an error about how much PE is there, or some such, your answer is correct.
