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How to find amount of water vapor present in gram moles? basic thermodynamics problem...?
I found (a) the volume to be 1.08 m^3. But I have no idea how to solve (b) and it's driving me to insanity. Please help!
2 Answers
- Peter HLv 76 years ago
A gram-mole of any substance is the equivalent of the molecular weight in grams. The molecular weight of water is 18, so a mole of water is 18 grams.
The number of molecules in a mole is given by Avogadro's constant, having the value 6.0221413 x 10^23.
- az_lenderLv 76 years ago
p = 1.5 MPa = 1.5 x 10^6 Pa; T = 440C = 713.16 K; R = 8.314 J/molK; and you were right about V, it's 1.08 m^3. Now solve pV = nRT, obtaining n = (pV)/(RT), just plug in the numbers and you'll have "n" which is the number of moles, around 250. Finally, part(c) just requires you to multiply the number of moles by Avogadro's number.
