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? asked in Science & MathematicsMathematics · 6 years ago

Maths Help!?

These questions are confusing me, please help! and please also explain how you work it out!

1. A car valued at 120000 at the start of 2010, depreciated in value by 3% over the next 2 years. How much did it lose in value over this period?

2. After a 15% reduction, the sale price of a car is 13175. What was the original price of the car?

All help appreciated!

4 Answers

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  • 6 years ago
    Favorite Answer

    1) After two years, the car is now worth 3% less. To solve this, set up as follows: 120000 x 0.03

    This gives you the lost value over that period of time. Note that I multiplied by 0.03 instead of 3 because 3 percent means 3/100 which is 0.03. This would give you an answer of 3600

    2) 15% has been deducted so 13175 is only 85% of the original price (100-15=85). So set up like the first one only this time, our unknown is the initial value so we should put a variable x for it.

    0.85x= 13175

    Divide both sides by 0.85 and you will get x= $15500

  • 6 years ago

    For question 1: multiply 120 000 by 0.03 (which is the 3%). This will give you a value of 3600. Therefore, the car lost $3600 in value over the 2 year span (it is now 116400).

    For question 2: Divide 13175 by .85 (representing an increase of 15%). This will give you $15500 as your value.

  • 6 years ago

    1.

    3% of 120000 is 3600

    Or did you mean it depreciated in value by 3% per year, so its final value is:

    120000 * (1 - (3/100))^2 = 112908

    So it lost 120000 - 112908 = 7092

    2.

    13175 / (1 - (15/100)) = 15500

  • In the power set of a set X we define the relation ARB ⇔ A ⊆ (X ∖ B). then:

    (1) R is reflective.

    (2) A R A ⇔ A = ∅.

    (3) The relation is transitive.

    (4) The relationship is not symmetrical.

    (5) None of the above.

    What is the correct answer and why;

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