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how do i put this in standard form for the quadtratic equation. 125 = 105t + -4.9t^2 ?
3 Answers
- JimLv 75 years ago
Typically Standard Form is whatever=0
125 = 105t + -4.9t^2
add 4.9t^2 subtract 105t
4.9t^2 -105t +125 = 0
((typically the first factor is positive))
- oubaasLv 75 years ago
4.9t^2-105t+125 = 0
as solving equation is :
t = (-b±√b^2-4ac)2a
a being the value of numerical part associated to t^2
b being the value of numerical part associated to t
c the third term
it is wise to arrange equation in such a way b is negative so that -b becomes a positive value and (-b)^2 is positive as well
