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Chemistry Help?

Consider the following reaction: 

2 A + 3 B2 ⇌ A2B6

The initial concentrations of A and B2 are 0.335 M and 0.940 M, respectively, with no A2B6 initially present. When the reaction comes to equilibrium, the concentration of A2B6 is found to be 1.00×10−2 M.

1.) What is the equilibrium concentration of A? (3 sig figs with units)

2.) What is the equilibrium concentration of B2? (3 sig figs with units)

3.) What is the value of the equilibrium constant? (3 sig figs with units)

2 Answers

Relevance
  • 5 years ago

    I figured it out.

    The answers are as follows:

    1.) 0.315 M

    2.) 0.910 M

    3.) 0.134

  • Jan
    Lv 7
    5 years ago

    2 A + 3 B2 ⇌ A2B6

    0.335 0.940.......0

    0.325...0.91....0.01

    so

    1) 0.33 M

    2) 0.91 M

    3)

    K = 0.01 / (0.325^2*0.91^3) M^-4 = 0.126 M^-4 = 0.13 M^-4

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