Can someone show me how to calculate the accelleration due to gravity ontop of everest? (8848km) above the surface of the earth.?

An object’s weight is equal to the Universal gravitational force.

m * g = G * M * m ÷ d^2

g = G * M ÷ d^2

d is the distance from the center of the earth to the object. This is sum of the radius of the earth and the object’s altitude.

d = 6.38 * 10^6 + 8,848,000 = 1.5228 * 10^7 meters

g = 6.67 * 10^-11 * 5.98 * 10^24 ÷ (1.5228 * 10^7)^2

This is approximately 1.72 m/s^2.

I hope this helps you to understand how to solve this type of problem. As look at the equation, you see that the value of g is inversely proportional to the square of the distance from the center of the earth to the object.

(6.38 * 10^6)^2 ÷ (1.5228 * 10^7)^2

This is approximately 0.17553. Let’s multiply this number by 9.8

g = 9.8 * 0.17553 = 1.720194

This is an easy way to solve this problem

Using the Earths Mass and Radius