What's the vertex & y intercept of the following 2: Y=2x^2 + 4x - 3 Y=4x^2 -8x + 9?

Odd that you used a small y for "y intercept" but a capital y in the equations. You should be consistent.

Y = 2x^2 + 4x - 3

Complete the square:

Y = 2(x^2 + 2x) - 3

Y = 2(x^2 + 2x + 1 - 1) - 3

Y = 2(x^2 + 2x + 1) - 2 - 3

Y = 2(x + 1)^2 - 5

The vertex is where the part in brackets is zero: x + 1 = 0, so x = -1, and Y = 2*0^2 - 5 = -5

At the y intercept, x = 0, so Y = -3

Y = 4x^2 - 8x + 9

Complete the square:

Y = 4(x^2 - 2x) + 9

Y = 4(x^2 - 2x + 1 - 1) + 9

Y = 4(x^2 - 2x + 1) - 4 + 9

Y = 4(x - 1)^2 + 5

The vertex is where the part in brackets is zero: x - 1 = 0, so x = 1, and Y = 4*0^2 + 5 = 5

At the y intercept, x = 0, so Y = 9

1) y = 2x^2 + 4x - 3 = 2x^2 + 4x + 2 - 5 = 2(x+1)^2 - 5. Vertex is @ (-1,-5). y-intercept occurs when x

= 0. y(0) = - 3. y-intercept s @ (0,-3).

2) y = 4x^2 - 8x + 9 = 4x^2 - 8x + 4 + 5 = 4(x - 1)^2 + 5. Vertex is @ (1,5). y-intercept is @ (0,9).

I'm really confused. Please explain aswell