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What is the direct stress and strain of a race car?

The crash structure of a simple race car chassis is made up of a tubular space frame design. Whilst each of the members of the space frame carries a load, one of the members is subjected to a greater load than all other members. The frame is manufactured from steel with a Young’s’ Modulus E of 200 GPa.

The member carrying the greatest load is subjected to a load of 1750N acting axially through the member. The space frame is made up of the same steel tube with an inner diameter of 20 mm and an outer diameter of 30 mm.

b. Calculate the direct stress in the member.

c. Calculate the Strain on this Strut.

d. If the original length of the member carrying the greatest load is 550mm, calculate the extension of the component when it is subjected to the load stated in part (a).

1 Answer

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  • 4 years ago

    b. Simple stress, σ = P/A

    σ = (1750N)/[(π/4)(30²–20²)]

    σ = 4.46 MPa

    c. Strain, ε = ∆L/L

    The relation between stress and strain is given by Hooke's law.

    ∆L/L = σ/E

    Therefore,

    ε = σ/E = 4.46 MPa / (200×10³)

    ε = 0.022x10^(-3)

    d. Given L=550 mm; P=1750 N

    ∆L = PL/AE = (1750)(550)/[(π/4)(30²–20²)(200×10³)]

    ∆L = 0.012 mm

    Conclusion: It has a very small deformation because of its elastic modulus being high (200 GPa).

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