Adrian, Ben and Charlie share some sweets in the ratio 6:3:8 Charlie got 26 more sweets than Adrian. Work out the total amount of sweets.?

Adrian, Ben and Charlie share some sweets in the ratio 6 : 3 : 8.

Charlie got 26 more sweets than Adrian.

A + B + C = 17x

2x = 26

x = 13

C - A = 26

The total amount of sweets is 221.

adrian has a sweets, ben b & charlie c

total = t

a + b + c = t

a = 2b

c = 4/3 a = a + 26

1/3 a = 26

a = 78, b = 39, c = 104

t = 78 + 39 + 104 = 221

Let x be the total

Adrian got (6/17)x

Ben got (3/17) x

Charlie got (8/17) x

(6/17) x + 26 = (8/17) x

multiply both sides by 17

6x+ (26)(17) = 8x

2x = (26)(17)

x = (26)(17) /2

x = 221 (total)

(2/17) of total = 26

total is 26*13 = 221

Apparently the "unit" is 13.

Adrian got 78, Ben got 39, Charlie got 104.

(a,b,c) share s's in ratio 6:3:8. Then (a,b,c) gets (6x,3x,8x) s's. c got 26 more s's than a. Then 8x-6x = 26, ie.,

x = 13. Total # s's = 6x+3x+8x = 17x = 17*13 = (15-2)(15+2) = 225-4 = 221.

Charlie-104

Adrian-78

Ben-35.....217 total