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what is the angle at which the dark fringe occurs?
Waves pass through two slits 9.3 cm apart. 4.2 m away from the slits is the first area of destructive interference. if the wavelength is 3.2 cm, what is the angle at which the dark fringe occurs?
14.0 degrees
10.9 degrees
12.6 degrees
9.91 degrees
1 Answer
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- JupiterSkyLv 64 years ago
d sinθ = (m+½)λ (for dark maxima)
For first order dark fringe, m=0
=>
sinθ = λ/2d
θ = arcsin (3.2/(2*9.3))
θ = 9.91°
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