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5 Answers
- lenpol7Lv 73 years ago
y^2 - 9 = (y - 3)(y +3)
y^2 + 10y + 21 = ( y + 3)(y + 7)
y^2 + 4y - 21 = ( y - 3)(y + 7)
- BeeLiz19Lv 73 years ago
factor all of them and find the part that's in common.
y^2 - 9 = difference of squares = (y-3)(y+3)
y^2 + 10y + 21 = factor by grouping = (y+7)(y+3)
y^2 + 4y - 21 = factor by grouping = (y+7)(y-3)
So all three of these don't have 1 particular thing in common.. BUT between the first two equations, (y+3) is common, and between the last two equations, (y+7) is common, and between the outside equations (y-3) is common.
SO our lowest common multiple is (y+3)(y-3)(y+7)
- BrainardLv 73 years ago
y^2 - 9 = (y + 3)(y - 3)
y^2 + 10y + 21 = (y + 3)(y + 7)
y^2 + 4y - 21 = (y + 7)(y - 3)
LCM = (x - 3)(x + 3)(x + 7)
= (x^2 - 9)(x + 7)
= x^3 + 7x - 9x - 63
= x^3 - 2x - 63
- KrishnamurthyLv 73 years ago
y^2 - 9, y^2 + 10y + 21, y^2 + 4y - 21
(y + 3)(y - 3), (y + 3)(y + 7), (y + 3)(y - 7)
LCM:
(y + 3) (y - 3) (y + 7) (y - 7)
y^4 - 58 y^2 + 441
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- Randy PLv 73 years ago
y^2 - 9 = (y + 3)(y - 3)
y^2 + 10y + 21 = (y + 3)(y + 7)
y^2 + 4y - 21 = (y + 7)(y - 3)
In order to be a multiple of all of these, it must contain all these factors that appear above: (y - 3), (y + 3), (y + 7). There aren't any others. Therefore if you multiply those three together you get the LCM of the three expresions.