Math question! having trouble with this question! Thank you guys!?

Two trains leave a train station at the same time.

One travels north at 9 miles per hour.

The other train travels south at 11 miles per hour.

In 4.6 hours the two trains will be 92 miles apart.

distance = rate * time

Let t = time traveled

Both trains are traveling in the same amount of time. Since they both leave at the same time in opposite directions the total distance travelled between them has to be 92.

9t + 11t = 92

20t = 92

t = 92/20 = 4.6

4.6 hours is the answer.

Relative speed is 20 mph

time = 92 / 20 = 4 • 6 hours = 4 h 36 min

Their combined speed is (9 + 11 = 20 mph). Therefore every hour their combined distance apart is 20 miles.

Time = Distance/Speed

= 92/20

= 4 12/20

= 4 3/5 hours

= 4 hours 36 minutes

Train 1 heads north @ 9 mph

Train 2 heads south @11mph

Trains 1 & 2 are separating from each other at the rate of 20 mph

Now d = rt where d = distance, r = rate and t =time. Then t = d/r and, for d = 92m and r = 20mph, t = 92m/[20m/h]

= 4.6 h

relative speed = 9+11 = 20 mph

time = distance/speed

92/20 (miles/mph)

= 4.6 hours

As our Algebra I teacher always used to say, "What equals what?"

By this he meant, "Set up your equation(s) in mathematical terms, to describe the situation."

It seems to me that for every hour that passes, the trains get twenty miles further apart.

Plug and chug.