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Physics collisions question?
Suppose a child drives a bumper car head on into the side rail, which exerts a force of 2400 N on the car for 0.500 s. (Assume the initial velocity is in the positive direction.)
(a)
What impulse (in kg · m/s) is imparted by this force? (Indicate the direction with the sign of your answer.)
Incorrect: Your answer is incorrect.
kg · m/s
(b)
Find the final velocity (in m/s) of the bumper car if its initial velocity was 2.90 m/s and the car plus driver have a mass of 200 kg. You may neglect friction between the car and floor. (Indicate the direction with the sign of your answer.)
m/s
1 Answer
- electron1Lv 72 years agoFavorite Answer
As the bumper car hits the side rail, its velocity will decrease. This means the force is negative.
There are two equations for impulse.
Eq#1, Impulse = Force * time
Eq#2, Impulse = Mass * Change of velocity
This is the change of momentum.
Impulse = -2400 * 0.5 = -1200 kg * m/s
(b)
Find the final velocity (in m/s) of the bumper car if its initial velocity was 2.90 m/s and the car plus driver have a mass of 200 kg. You may neglect friction between the car and floor. (Indicate the direction with the sign of your answer.)
m/s
The first step is to determine the acceleration.
-2400 = 200 * a
a = -12 m/s^2
Let’s use the following equation to determine the final velocity.
vf = vi + a * t
vf = 2.90 + -12 * 0.5 = -3.1 m/s
The negative sign means the bumper car is moving away from the side rail after the collision. I hope this is helpful for you.
